1860 United States presidential election in New Hampshire
Election in New Hampshire
 | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
 County Results Lincoln 40-50% 50-60% 60-70%
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
The 1860 United States presidential election in New Hampshire took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose five electors of the Electoral College, who voted for president and vice president.
New Hampshire was won by Republican candidate Abraham Lincoln, who won the state by 17.64%.
Results
| 1860 United States presidential election in New Hampshire[1] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Abraham Lincoln of Illinois | Hannibal Hamlin of Maine | 37,519 | 56.90% | 5 | 100.00% | ||
| Democratic | Stephen Arnold Douglas of Illinois | Herschel Vespasian Johnson of Georgia | 25,887 | 39.26% | 0 | 0.00% | ||
| Southern Democratic | John Cabell Breckinridge of Kentucky | Joseph Lane of Oregon | 2,125 | 3.22% | 0 | 0.00% | ||
| Constitutional Union | John Bell of Tennessee | Edward Everett of Massachusetts | 412 | 0.62% | 0 | 0.00% | ||
| Total | 65,943 | 100.00% | 5 | 100.00% | ||||
See also
References
- ^ "1860 Presidential General Election Results - New Hampshire".
| |||||
|---|---|---|---|---|---|
| Presidential elections | |||||
| Senate elections |
| ||||
| House elections | |||||
| Gubernatorial elections |
| ||||
| Legislative elections |
| ||||
State results of the 1860 U.S. presidential election | ||
|---|---|---|
|  | |
  | This New Hampshire elections-related article is a stub. You can help Wikipedia by expanding it. |
- v
- t
- e
