1824 United States presidential election in Delaware

1824 United States presidential election in Delaware

← 1820 October 26 – December 2, 1824 1828 →

Nominee William H. Crawford John Quincy Adams Party Democratic-Republican Democratic-Republican Home state Georgia Massachusetts Running mate Nathaniel Macon John C. Calhoun Electoral vote 2 1

President before election James Monroe Democratic-Republican Elected President John Quincy Adams Democratic-Republican

Elections in Delaware
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Wilmington Mayoral elections 2012 2016 2020 2024
v t e

The 1824 United States presidential election in Delaware took place between October 26 and December 2, 1824, as part of the 1824 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

During this election, the Democratic-Republican Party was the only major national party, and four different candidates from this party sought the Presidency. Delaware cast two electoral votes for William H. Crawford and one for John Quincy Adams.

Results

See also

• United States presidential elections in Delaware

References